Answer
$\sec^2 (5x-1)$
Work Step by Step
Need to solve.
$\dfrac{d(\dfrac{1}{5}\tan(5x-1)+C)}{dx}=(\dfrac{1}{5})\dfrac{5}{\cos^2(5x-1)}$
or, $=\sec^2 (5x-1)$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 4: Applications of Derivatives - Section 4.7 - Antiderivatives - Exercises 4.7 - Page 239: 59
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