Answer
$2x+\cot x+C$
Work Step by Step
Integrate. $ \int 1 dx- \int (\cot^2 x )d x$
Thus, we have $ \int 1 dx- \int (\cot^2 x )d x= x-(-\cot x)+x+C$
or, $=2x+\cot x+C$
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