Answer
$x^2+2x^{-1}+C$
Work Step by Step
As we know $\int x^n dx=\dfrac{x^{n+1}}{n+1}+C$
Simplify. $\int 2x(1-x^{-3}) dx$
Thus, $\int 2x(1-x^{-3}) dx=\int (2x-2x^{-2}) dx=x^2+\dfrac{2}{x}+C=x^2+2x^{-1}+C$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 4: Applications of Derivatives - Section 4.7 - Antiderivatives - Exercises 4.7 - Page 239: 31
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