Answer
$\tan \theta +C$
Work Step by Step
Integrate. $\int \dfrac{\csc \theta}{(\cos \theta \cot \theta)}$
Thus, we have $\int \dfrac{\csc \theta}{(\cos \theta \cot \theta)}=\int \dfrac{1/\sin \theta}{\cos \theta (\dfrac{\cos \theta}{\sin \theta})}$
or, $ =\int sec^2 \theta$
or, $=\tan \theta +C$