Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 4: Applications of Derivatives - Section 4.7 - Antiderivatives - Exercises 4.7 - Page 239: 56

Answer

$\tan \theta +C$

Work Step by Step

Integrate. $\int \dfrac{\csc \theta}{(\cos \theta \cot \theta)}$ Thus, we have $\int \dfrac{\csc \theta}{(\cos \theta \cot \theta)}=\int \dfrac{1/\sin \theta}{\cos \theta (\dfrac{\cos \theta}{\sin \theta})}$ or, $ =\int sec^2 \theta$ or, $=\tan \theta +C$
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