Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 4: Applications of Derivatives - Section 4.7 - Antiderivatives - Exercises 4.7 - Page 239: 55

Answer

$-\cos \theta +\theta +C$

Work Step by Step

Integrate. $\int (\cos \theta \tan \theta) d\theta + \int (\cos \theta \sec \theta) d\theta $ Thus, $\int (\cos \theta \tan \theta) d\theta + \int (\cos \theta \sec \theta) d\theta=\int [\cos \theta (\dfrac{\sin \theta}{\cos \theta}) d\theta + \int \cos \theta (\dfrac{1}{\cos \theta})] d\theta$ or, $=-\cos \theta +\theta +C$
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