Chapter 4: Applications of Derivatives - Section 4.7 - Antiderivatives - Exercises 4.7 - Page 239: 36

$$5\cos t + C $$

$$\eqalign{ & \int {\left( { - 5\sin t} \right)} dt \cr & = - 5\int {\sin t} dt \cr & {\text{integrate by using }}\int {\sin t} dt = - \cos t + C \cr & = - 5\left( { - \cos t} \right) + C \cr & {\text{simplifying, we get:}} \cr & = 5\cos t + C \cr} $$