#### Answer

$\dfrac{1}{(x+1)^2}$

#### Work Step by Step

Need to solve.
$\dfrac{d((\dfrac{-1}{x+1})+C)}{dx}=(x+1)^{-2}$
or, $=\dfrac{1}{(x+1)^2}$

Published by
Pearson

ISBN 10:
0-32187-896-5

ISBN 13:
978-0-32187-896-0

$\dfrac{1}{(x+1)^2}$

Need to solve.
$\dfrac{d((\dfrac{-1}{x+1})+C)}{dx}=(x+1)^{-2}$
or, $=\dfrac{1}{(x+1)^2}$

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