Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 4: Applications of Derivatives - Section 4.7 - Antiderivatives - Exercises 4.7 - Page 239: 39

Answer

$3 \cot x +C $

Work Step by Step

Simplify. $\int (-3 \csc^2 x) dx$ Thus, we have $\int (-3 \csc^2 x) dx=-3(-\cot x)+C=3 \cot x +C $
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