Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 4: Applications of Derivatives - Section 4.7 - Antiderivatives - Exercises 4.7 - Page 239: 38


$\dfrac{3}{5} \sin 5\theta +C $

Work Step by Step

Here, $\int (3 \cos 5\theta) d\theta=\dfrac{3}{5} \sin 5\theta +C $ Also, $\dfrac{d}{d \theta}(\dfrac{3}{5} \sin 5\theta +C )=3 \cos 5\theta$ Thus, the derivative of the integral is integrand. So, the answer is correct.
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