Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 4: Applications of Derivatives - Section 4.7 - Antiderivatives - Exercises 4.7 - Page 239: 29


$4y^2-\dfrac{2y^{3/4}}{3/4} +C=4y^2-\dfrac{8y^{3/4}}{3} +C$

Work Step by Step

As we know $\int x^n dx=\dfrac{x^{n+1}}{n+1}+C$ Simpify. $\int (8y-\dfrac{2}{y^{1/4}})dy$ Thus, $\int (8y-\dfrac{2}{y^{1/4}})dy=4y^2-\dfrac{2y^{3/4}}{3/4} +C=4y^2-\dfrac{8y^{3/4}}{3} +C$
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