Answer
$4y^2-\dfrac{2y^{3/4}}{3/4} +C=4y^2-\dfrac{8y^{3/4}}{3} +C$
Work Step by Step
As we know $\int x^n dx=\dfrac{x^{n+1}}{n+1}+C$
Simpify. $\int (8y-\dfrac{2}{y^{1/4}})dy$
Thus, $\int (8y-\dfrac{2}{y^{1/4}})dy=4y^2-\dfrac{2y^{3/4}}{3/4} +C=4y^2-\dfrac{8y^{3/4}}{3} +C$
