Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 4: Applications of Derivatives - Section 4.7 - Antiderivatives - Exercises 4.7 - Page 239: 67

Answer

True

Work Step by Step

$\dfrac{d}{dx}[(\dfrac{x+3}{x-2})^3+C] =(3)[ (\dfrac{x+3}{x-2})^2 (\dfrac{5}{(x-2)^2})]$ or, $=-15\dfrac{(x+3)^2}{(x-2)^4}$ Thus, the given statement is true.
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