Answer
$\dfrac{1}{(x+1)^2}$
Work Step by Step
Need to solve.
$\dfrac{d(\dfrac{x}{x+1}+C)}{dx}=\dfrac{d(1-\dfrac{1}{x+1}+C)}{dx}=(x+1)^{-2}$
or, $=\dfrac{1}{(x+1)^2}$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 4: Applications of Derivatives - Section 4.7 - Antiderivatives - Exercises 4.7 - Page 239: 62
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