Answer
$-\cot x-x+C$
Work Step by Step
Integrate. $ \int (\csc^2 x )d x-\int 1 dx$
Thus, we have $ \int (\csc^2 x )d x-\int 1 dx= -\cot x-x+C$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 4: Applications of Derivatives - Section 4.7 - Antiderivatives - Exercises 4.7 - Page 239: 53
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