## Thomas' Calculus 13th Edition

$\bf{Graph (b)}$
Since, we have $\dfrac{dy}{dx}=2x$ This implies, $y=x^2+C$ Plug $x=1,y=4$ in equation $y=x^2+C$ for solving $C$. we have $C=3$ Hence, $y=x^2+3$; which shows $\bf{Graph (b)}$