Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 4: Applications of Derivatives - Section 4.7 - Antiderivatives - Exercises 4.7 - Page 240: 69

Answer

$\bf{Graph (b)}$

Work Step by Step

Since, we have $\dfrac{dy}{dx}=2x$ This implies, $y=x^2+C$ Plug $x=1,y=4$ in equation $y=x^2+C$ for solving $C$. we have $C=3$ Hence, $y=x^2+3$; which shows $\bf{Graph (b)}$
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