Answer
$y=3x^3-2x^2+5x+10$
Work Step by Step
T The anti-derivative for $\dfrac{dy}{dx}=9x^2-4x+5$ is $y=3x^3-2x^2+5x+C$
Apply the initial conditions $y(-1)=0$
This implies $-3-2-5+C=0$
or, $C=10$
Hence, $y=3x^3-2x^2+5x+10$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 4: Applications of Derivatives - Section 4.7 - Antiderivatives - Exercises 4.7 - Page 240: 74
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