Answer
$s=t+\sin t+4$
Work Step by Step
The anti-derivative for $\dfrac{ds}{dx}=1+\cos t$ is $s=t+\sin t+C$
Apply the initial conditions $s(0)=4$ to get the value of $C$.
This implies, $4=0+\sin 0+C$ or, $ C=4$
Hence, $s=t+\sin t+4$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 4: Applications of Derivatives - Section 4.7 - Antiderivatives - Exercises 4.7 - Page 240: 77
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