Answer
$y=2x$
Work Step by Step
The anti-derivative for $\dfrac{d^2y}{dx^2}=0$ is $\dfrac{dy}{dx}=c$; $y=cx+c'$
Now, apply Initial conditions $y'(0)=2 ; y(0)=0$,we have
This implies $c=2$ and $0+c'=0$ and $ c'=0$
Hence, $y=2x$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 4: Applications of Derivatives - Section 4.7 - Antiderivatives - Exercises 4.7 - Page 240: 84
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