Chapter 4: Applications of Derivatives - Section 4.7 - Antiderivatives - Exercises 4.7 - Page 240: 71

$y=x^2-7x+10$

The anti-derivative for $\dfrac{dy}{dx}=2x-7$ is $y=x^2-7x+C$ Now, apply the initial conditions in equation $y=x^2-7x+C$ for solving the value of $C$. This impliest $2^2-7(2)x+C=0 $ and $ C=10$ Hence, $y=x^2-7x+10$