Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set - Page 417: 91

Answer

$\text{the domain is the interval } (-\infty,\infty) $

Work Step by Step

Since the index of the radical expression in the given function, $ f(x)=\sqrt[3]{x}-1 ,$ is odd (index is equal to $3$), then the radicand can be any number. Hence, $ \text{the domain is the interval } (-\infty,\infty) .$ Using the table of values below, the graph is determined.
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