Answer
$\text{the domain is the interval }
(-\infty,\infty)
$
Work Step by Step
Since the index of the radical expression in the given function, $
f(x)=\sqrt[3]{x}-1
,$ is odd (index is equal to $3$), then the radicand can be any number. Hence, $
\text{the domain is the interval }
(-\infty,\infty)
.$
Using the table of values below, the graph is determined.