Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set - Page 417: 36

Answer

$x^{5}$

Work Step by Step

$\sqrt[4] (x^{20})=x^{5}$, because $(x^{5})^{4}=x^{5}\times x^{5}\times x^{5}\times x^{5}=x^{5+5+5+5}=x^{20}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.