Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set - Page 417: 56

Answer

-5

Work Step by Step

$\sqrt[3] 125=5$, because $5^{3}=5\times5\times5=125$ Therefore, $-\sqrt[3] 125=-5$. In this case, we are just taking the opposite of $\sqrt[3] 125$, which is $-(5)=-5$
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