Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set: 64

Answer

$-2a^{7}b^{2}$

Work Step by Step

$\sqrt[3] (-8a^{21}b^{6})=-2a^{7}b^{2}$, because $(-2a^{7}b^{2})^{3}=-2a^{7}b^{2}\times -2a^{7}b^{2}\times -2a^{7}b^{2}=(-2\times-2\times-2)\times a^{7+7+7}\times b^{2+2+2}=-8a^{21}b^{6}$
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