Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set - Page 417: 60

Answer

$y^{4}$

Work Step by Step

$\sqrt[3] (y^{12})=y^{4}$, because $(y^{4})^{3}=y^{4}\times y^{4}\times y^{4}=y^{4+4+4}=y^{12}$
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