Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set: 72

Answer

$\frac{y^{5}}{3x^{3}}$

Work Step by Step

$\sqrt (\frac{y^{10}}{9x^{6}})=\frac{y^{5}}{3x^{3}}$, because $(\frac{y^{5}}{3x^{3}})^{2}=\frac{y^{5}}{3x^{3}}\times\frac{y^{5}}{3x^{3}}=\frac{y^{5+5}}{(3\times3)\times x^{3+3}}=\frac{y^{10}}{9x^{6}}$
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