Answer
$-3x^{4}y^{3}$
Work Step by Step
$\sqrt[3] (-27x^{12}y^{9})=-3x^{4}y^{3}$, because
$(-3x^{4}y^{3})^{3}=-3x^{4}y^{3}\times -3x^{4}y^{3}\times -3x^{4}y^{3}=(-3\times-3\times-3)\times x^{4+4+4}\times y^{3+3+3}=-27x^{12}y^{9}$
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set - Page 417: 63
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