Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set: 62

Answer

$3x^{2}y^{3}$

Work Step by Step

$\sqrt (9x^{4}y^{6})=3x^{2}y^{3}$, because $(3x^{2}y^{3})^{2}=3x^{2}y^{3}\times 3x^{2}y^{3}=(3\times3)\times x^{2+2}\times y^{3+3}=9x^{4}y^{6}$
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