Answer
$3x^{2}y^{3}$
Work Step by Step
$\sqrt (9x^{4}y^{6})=3x^{2}y^{3}$, because $(3x^{2}y^{3})^{2}=3x^{2}y^{3}\times 3x^{2}y^{3}=(3\times3)\times x^{2+2}\times y^{3+3}=9x^{4}y^{6}$
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set - Page 417: 62
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