## Intermediate Algebra (6th Edition)

$|x+2|$
We are told that $\sqrt[n] a^{n}=|a|$ when n is an even positive integer. In this case, we must factor in order to find $a$. $x^{2}+4x+4=(x+2)(x+2)=(x+2)^{2}$ Therefore, $a=(x+2)$. $\sqrt (x+2)^{2}=|x+2|$