Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set - Page 417: 59

Answer

$y^{6}$

Work Step by Step

$\sqrt (y^{12})=y^{6}$, because $(y^{6})^{2}=y^{6}\times y^{6}=y^{6+6}=y^{12}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.