Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set: 58



Work Step by Step

$\sqrt (16x^{8})=4x^{4}$, because $(4x^{4})^{2}=4x^{4}\times4x^{4}=(4\times4)\times x^{4+4}=16x^{8}$
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