Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set - Page 417: 47

Answer

$2|x|$

Work Step by Step

We are told that $\sqrt[n] a^{n}=|a|$ when n is an even positive integer. In this case, $4x^{2}=(2x)^{2}$, so $a=2x$. $\sqrt (a^{2})=|2x|=2|x|$
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