Answer
$\frac{x^{10}}{2y}$
Work Step by Step
$\sqrt (\frac{x^{20}}{4y^{2}})=\frac{x^{10}}{2y}$, because $(\frac{x^{10}}{2y})^{2}=\frac{x^{10}}{2y}\times\frac{x^{10}}{2y}=\frac{x^{10+10}}{(2\times2)\times y^{1+1}}=\frac{x^{20}}{4y^{2}}$
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set - Page 417: 71
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