Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set: 75

Answer

$\frac{x}{2}$

Work Step by Step

$\sqrt[4] (\frac{x^{4}}{16})=\frac{x}{2}$, because $(\frac{x}{2})^{4}=\frac{x}{2}\times\frac{x}{2}\times \frac{x}{2}\times \frac{x}{2}=\frac{x^{1+1+1+1}}{2\times2\times2\times2}=\frac{x^{4}}{16}$
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