Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set: 37



Work Step by Step

$\sqrt[6] (64x^{12})=2x^{2}$, because $(2x^{2})^{6}=2x^{2}\times 2x^{2}\times 2x^{2}\times 2x^{2}\times 2x^{2}\times 2x^{2}=$ $(2\times2\times2\times2\times2\times2)\times x^{2+2+2+2+2+2}=64x^{12}$
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