Answer
$2x^{2}$
Work Step by Step
$\sqrt[6] (64x^{12})=2x^{2}$, because $(2x^{2})^{6}=2x^{2}\times 2x^{2}\times 2x^{2}\times 2x^{2}\times 2x^{2}\times 2x^{2}=$
$(2\times2\times2\times2\times2\times2)\times x^{2+2+2+2+2+2}=64x^{12}$
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