Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set: 32

Answer

not a real number

Work Step by Step

$\sqrt (-16)$, is not a real number, because there is no number $a$, such that $a^{2}=-16$. For example, $4^{2}=16$ and $(-4)^{2}=16$
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