Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set: 61

Answer

$5ab^{10}$

Work Step by Step

$\sqrt (25a^{2}b^{20})=5ab^{10}$, because $(5ab^{10})^{2}=5ab^{10}\times 5ab^{10}=(5\times5)\times a^{1+1}\times b^{10+10}=25a^{2}b^{20}$
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