Answer
$\text{the domain is the interval }
[3,\infty)
$
Work Step by Step
The radicand of the given function, $
f(x)=\sqrt{x-3}
,$ should be a nonnegative number. That is,
\begin{array}{l}\require{cancel}
x-3\ge0
\\
x\ge3
.\end{array}
Hence, $
\text{the domain is the interval }
[3,\infty)
.$
Using the table of values below, the graph is determined.