Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set: 68



Work Step by Step

$\sqrt[5] (-243x^{5}z^{15})=-3xz^{3}$, because $(-3xz^{3})^{5}=-3xz^{3}\times-3xz^{3}\times-3xz^{3}\times-3xz^{3}\times-3xz^{3}=$ $(-3\times-3\times-3\times-3\times-3)\times x^{1+1+1+1+1}\times z^{3+3+3+3+3}=-243x^{5}z^{15}$
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