Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set: 69

Answer

$\frac{5}{7}$

Work Step by Step

$\sqrt (\frac{25}{49})=\frac{5}{7}$, because $(\frac{5}{7})^{2}=\frac{5}{7}\times\frac{5}{7}=\frac{25}{49}$
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