Answer
$a^{4}b$
Work Step by Step
$\sqrt[4] (a^{16}b^{4})=a^{4}b$, because
$(a^{4}b)^{4}=a^{4}b\times a^{4}b\times a^{4}b\times a^{4}b=a^{4+4+4+4}\times b^{1+1+1+1}=a^{16}b^{4}$
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set - Page 417: 65
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