Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set - Page 417: 33

Answer

-2

Work Step by Step

$\sqrt[5] (-32)=-2$, because $(-2)^{5}=-2\times-2\times-2\times-2\times-2=-32$
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