Answer
$-2x^{3}$
Work Step by Step
$\sqrt[5] (-32x^{15})=-2x^{3}$, because $(-2x^{3})^{5}=-2x^{3}\times -2x^{3}\times -2x^{3}\times -2x^{3}\times -2x^{3}=$
$(-2\times-2\times-2\times-2\times-2)\times x^{3+3+3+3+3}=-32x^{15}$
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