Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 12 - Section 12.3 - Geometric Sequences - 12.3 Exercises - Page 865: 74

Answer

The series is convergent. The sum of the infinite geometric series is $-\frac{1000}{117}$

Work Step by Step

The series is convergent because |r| $\lt$ 1. r (the common ratio) = $-\frac{3}{10}$ since each term is multiplied by $-\frac{3}{10}$. Use the formula for the sum of an infinite geometric series: S = $\frac{a}{1-r}$ and plug in the first term, $-\frac{100}{9}$, for a, and the common ratio, $-\frac{3}{10}$ for r: S = $\frac{-\frac{100}{9}}{1-(-\frac{3}{10})} = \frac{-\frac{100}{9}}{\frac{13}{10}}$ = $-\frac{1000}{117}$
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