Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 12 - Section 12.3 - Geometric Sequences - 12.3 Exercises - Page 865: 40

Answer

The sixth term is -648

Work Step by Step

1. Find the common ratio. The 2nd term ($-\frac{1}{2}$) is the first term ($\frac{1}{12}$) multiplied by -6 so the common ratio, r, = -6. 2. Find the first term: The first term is given as $\frac{1}{12}$. The first term = a. 3. Create a formula for the geometric sequence in the form $a_{n} = a(r)^{n-1}$ : $a_n = \frac{1}{12}(-6)^{n-1}$ 4. Plug in n = 6 to get the sixth term: $a_n = \frac{1}{12}(-6)^{6-1}$ $a_n = \frac{1}{12}(-6)^{5}$ = -648.
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