Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 12 - Section 12.3 - Geometric Sequences - 12.3 Exercises - Page 865: 31

Answer

The common ratio is -0.3. The fifth term is .00243. $a_{n} = 0.3(-0.3)^{n-1}$

Work Step by Step

We are given the terms 0.3, -0.09, 0.027, -0.0081. Since each term is multiplied by -.3 to get the next term the common ratio is -.3. The fifth term = the fourth term $\times$ -.3. (the common ratio). So the fifth term = -.0081 $\times $ -.3 = .00243. To write an equation for the nth term of the form $a_{n} = a(r)^{n-1}$ plug in the first term for a (.1) and the common ratio for r (-0.3) to get $a_{n} = 0.3(-0.3)^{n-1}$
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