Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 12 - Section 12.3 - Geometric Sequences - 12.3 Exercises - Page 865: 70

Answer

The series converges. The sum of the infinite geometric series is $\frac{1}{648}$

Work Step by Step

The series is convergent because |r| $\lt$ 1. r (the common ratio) = $\frac{1}{9}$ since each term is multiplied by $\frac{1}{9}$. Use the formula for the sum of an infinite geometric series: S = $\frac{a}{1-r}$ and plug in the first term, $\frac{1}{729}$, for a, and the common ratio, $\frac{1}{9}$ for r: S = $\frac{\frac{1}{729}}{1-\frac{1}{9}} = \frac{\frac{1}{729}}{\frac{8}{9}}$ = $\frac{1}{648}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.