Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 12 - Section 12.3 - Geometric Sequences - 12.3 Exercises - Page 865: 45

Answer

$1728, 1296, 972$

Work Step by Step

A geometric sequence is a sequence whose terms are obtained by multiplying each term by the same fixed constant $r$ to get the next term. A geometric sequence has the form $a, ar, ar^{2}, ar^{3}, \ldots$ The number $a$ is the first term of the sequence, and the number $r $is the common ratio. The nth term of the sequence is $\quad a_{n}=ar^{n-1}$ -------------- Given: $r=0.75,\quad a_{4}=729,$ Using $a_{n+1}=a_{n}r$, we work our way back... $a_{4}=a_{3}r$ leads to $a_{3}=729\div 0.75=972$ $a_{3}=a_{2}r$ leads to $a_{2}=972\div 0.75=1296$ $a_{2}=a_{1}r$ leads to $a_{1}=1296\div 0.75=1728$
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