Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 12 - Section 12.3 - Geometric Sequences - 12.3 Exercises - Page 865: 39

Answer

The fourth term = $\frac{24}{25}$

Work Step by Step

1. Find the common ratio. The 2nd term (6) is the first term (15) multiplied by $\frac{2}{5}$ so the common ratio, r, = $\frac{2}{5}$ 2. Find the first term: The first term is given as 15. The first term = a. 3. Create a formula for the geometric sequence in the form $a_{n} = a(r)^{n-1}$ : $a_n = 15(\frac{2}{5})^{n-1}$ 4. Plug in n = 4 to get the fourth term: $a_n = 15(\frac{2}{5})^{4-1}$ = $15(\frac{2}{5})^{3}$ =$ \frac{24}{25}$
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