Chapter 10 - Systems of Equations and Inequalities - Section 10.6 Systems of Nonlinear Equations - 10.6 Assess Your Understanding - Page 794: 9

See graphs, $(1,1)$

1. See graphs 2. Use $y=\sqrt {x}$ in $y=2-x$ to get $2-x=\sqrt x$ or $x+\sqrt x-2=0$ 3. Let $z=\sqrt x$, we have $z^2+z-2=0$ or $(z+2)(z-1)=0$, thus $z=-2, 1$ 4. For $\sqrt x=-2$, there is no real solution. 5. For $\sqrt x=1$, we have $x=1$ 6. Use the 2nd equation again to get $y=1$ 7. We can find the intersect(s) $(1,1)$