Answer
See graphs , $(4+\sqrt 2,4-\sqrt 2), (4-\sqrt 2,4+\sqrt 2)$
Work Step by Step
1. See graphs for $y=\sqrt {36-x^2}$ and $y=8-x$
2. To find the intersect(s) using the two equations, we have $\sqrt {36-x^2}=8-x\Longrightarrow 36-x^2=64-16x+x^2\Longrightarrow x^2-8x+14=0\Longrightarrow x=\frac{8\pm\sqrt {64-4(14)}}{2}=4\pm\sqrt 2$
3. Use the above results with the 2nd equation to get the intersect(s) $(4+\sqrt 2,4-\sqrt 2), (4-\sqrt 2,4+\sqrt 2)$
