Answer
$(\frac{8}{3},\frac{2\sqrt {10}}{3}),(-\frac{8}{3},\frac{2\sqrt {10}}{3}),(\frac{8}{3},-\frac{2\sqrt {10}}{3}),(-\frac{8}{3},-\frac{2\sqrt {10}}{3})$
Work Step by Step
1. Multiply 2 to the 2nd equation and add to the 1st, we have
$9x^2=64$, thus $x^2=\frac{64}{9}$ and $x=\pm\frac{8}{3}$
2. Use the 2nd equation, $4(\pm\frac{8}{3})^2-y^2=24$ or $y^2=\frac{40}{9}$, thus $y=\pm\frac{2\sqrt {10}}{3}$
3. The solutions $(\frac{8}{3},\frac{2\sqrt {10}}{3}),(-\frac{8}{3},\frac{2\sqrt {10}}{3}),(\frac{8}{3},-\frac{2\sqrt {10}}{3}),(-\frac{8}{3},-\frac{2\sqrt {10}}{3})$
